Base | Representation |
---|---|
bin | 101000000101011001… |
… | …110000011110110111 |
3 | 11010002112221100102212 |
4 | 220011121300132313 |
5 | 1201121304424343 |
6 | 31434503124035 |
7 | 3052402415630 |
oct | 500531603667 |
9 | 133075840385 |
10 | 43040311223 |
11 | 17287151948 |
12 | 841214361b |
13 | 409bc0c1a0 |
14 | 21242a8887 |
15 | 11bd88ec18 |
hex | a056707b7 |
43040311223 has 32 divisors (see below), whose sum is σ = 53270743680. Its totient is φ = 33862717440.
The previous prime is 43040311199. The next prime is 43040311297. The reversal of 43040311223 is 32211304034.
43040311223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 43040311223 - 26 = 43040311159 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43040317223) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24057413 + ... + 24059201.
It is an arithmetic number, because the mean of its divisors is an integer number (1664710740).
Almost surely, 243040311223 is an apocalyptic number.
43040311223 is a deficient number, since it is larger than the sum of its proper divisors (10230432457).
43040311223 is a wasteful number, since it uses less digits than its factorization.
43040311223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3147.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 43040311223 its reverse (32211304034), we get a palindrome (75251615257).
The spelling of 43040311223 in words is "forty-three billion, forty million, three hundred eleven thousand, two hundred twenty-three".
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