Base | Representation |
---|---|
bin | 10011100100101001001111… |
… | …00100110110000001111111 |
3 | 12122101122010121212202211202 |
4 | 21302110213210312001333 |
5 | 21120134001444240020 |
6 | 231312314101010115 |
7 | 12031401326142326 |
oct | 1162244744660177 |
9 | 178348117782752 |
10 | 43040531243135 |
11 | 127944289056a8 |
12 | 49b16629b393b |
13 | 1b02921250a6a |
14 | a8b25c3490bd |
15 | 4e98b28d2e75 |
hex | 27252793607f |
43040531243135 has 4 divisors (see below), whose sum is σ = 51648637491768. Its totient is φ = 34432424994504.
The previous prime is 43040531243123. The next prime is 43040531243153. The reversal of 43040531243135 is 53134213504034.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 43040531243135 - 220 = 43040530194559 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4304053124309 + ... + 4304053124318.
It is an arithmetic number, because the mean of its divisors is an integer number (12912159372942).
Almost surely, 243040531243135 is an apocalyptic number.
43040531243135 is a deficient number, since it is larger than the sum of its proper divisors (8608106248633).
43040531243135 is an equidigital number, since it uses as much as digits as its factorization.
43040531243135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8608106248632.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 43040531243135 its reverse (53134213504034), we get a palindrome (96174744747169).
The spelling of 43040531243135 in words is "forty-three trillion, forty billion, five hundred thirty-one million, two hundred forty-three thousand, one hundred thirty-five".
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