Base | Representation |
---|---|
bin | 111110101000111010101… |
… | …100101011100110100101 |
3 | 120020111202221020100121021 |
4 | 332220322230223212211 |
5 | 1031011200224201203 |
6 | 13053251310251141 |
7 | 622664364325330 |
oct | 76507254534645 |
9 | 16214687210537 |
10 | 4304542022053 |
11 | 140a6008302a9 |
12 | 5962ba4b6ab1 |
13 | 252bbb924b50 |
14 | 10c4ab7a9617 |
15 | 76e872a85bd |
hex | 3ea3ab2b9a5 |
4304542022053 has 32 divisors (see below), whose sum is σ = 5543746500096. Its totient is φ = 3251219482368.
The previous prime is 4304542022021. The next prime is 4304542022083. The reversal of 4304542022053 is 3502202454034.
4304542022053 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4304542022053 - 25 = 4304542022021 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4304542022003) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11882401 + ... + 12239302.
It is an arithmetic number, because the mean of its divisors is an integer number (173242078128).
Almost surely, 24304542022053 is an apocalyptic number.
It is an amenable number.
4304542022053 is a deficient number, since it is larger than the sum of its proper divisors (1239204478043).
4304542022053 is a wasteful number, since it uses less digits than its factorization.
4304542022053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24121813.
The product of its (nonzero) digits is 115200, while the sum is 34.
Adding to 4304542022053 its reverse (3502202454034), we get a palindrome (7806744476087).
The spelling of 4304542022053 in words is "four trillion, three hundred four billion, five hundred forty-two million, twenty-two thousand, fifty-three".
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