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43053433 is a prime number
BaseRepresentation
bin1010010000111…
…1000101111001
310000000100012121
42210033011321
542010202213
64134441241
71031643133
oct244170571
9100010177
1043053433
1122336755
1212503221
138bc5607
145a0a053
153ba688d
hex290f179

43053433 has 2 divisors, whose sum is σ = 43053434. Its totient is φ = 43053432.

The previous prime is 43053431. The next prime is 43053467. The reversal of 43053433 is 33435034.

43053433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42029289 + 1024144 = 6483^2 + 1012^2 .

It is a cyclic number.

It is not a de Polignac number, because 43053433 - 21 = 43053431 is a prime.

Together with 43053431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 43053398 and 43053407.

It is not a weakly prime, because it can be changed into another prime (43053431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21526716 + 21526717.

It is an arithmetic number, because the mean of its divisors is an integer number (21526717).

Almost surely, 243053433 is an apocalyptic number.

It is an amenable number.

43053433 is a deficient number, since it is larger than the sum of its proper divisors (1).

43053433 is an equidigital number, since it uses as much as digits as its factorization.

43053433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 25.

The square root of 43053433 is about 6561.5114874547. The cubic root of 43053433 is about 350.4848599792.

Adding to 43053433 its reverse (33435034), we get a palindrome (76488467).

The spelling of 43053433 in words is "forty-three million, fifty-three thousand, four hundred thirty-three".