4311031220021 has 2 divisors, whose sum is σ = 4311031220022. Its totient is φ = 4311031220020.

The previous prime is 4311031219987. The next prime is 4311031220183. The reversal of 4311031220021 is 1200221301134.

4311031220021 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3015133579396 + 1295897640625 = 1736414^2 + 1138375^2 .

It is a cyclic number.

It is not a de Polignac number, because 4311031220021 - 2¹⁰ = 4311031218997 is a prime.

It is a super-2 number, since 2×4311031220021² (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4311031219975 and 4311031220002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4311031120021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2155515610010 + 2155515610011.

It is an arithmetic number, because the mean of its divisors is an integer number (2155515610011).

Almost surely, 2^{4311031220021} is an apocalyptic number.

It is an amenable number.

4311031220021 is a deficient number, since it is larger than the sum of its proper divisors (1).

4311031220021 is an equidigital number, since it uses as much as digits as its factorization.

4311031220021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 4311031220021 its reverse (1200221301134), we get a palindrome (5511252521155).

The spelling of 4311031220021 in words is "four trillion, three hundred eleven billion, thirty-one million, two hundred twenty thousand, twenty-one".