4311241214141 has 2 divisors, whose sum is σ = 4311241214142. Its totient is φ = 4311241214140.

The previous prime is 4311241214129. The next prime is 4311241214143. The reversal of 4311241214141 is 1414121421134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4310315776900 + 925437241 = 2076130^2 + 30421^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4311241214141 is a prime.

Together with 4311241214143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4311241214143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2155620607070 + 2155620607071.

It is an arithmetic number, because the mean of its divisors is an integer number (2155620607071).

Almost surely, 2^{4311241214141} is an apocalyptic number.

It is an amenable number.

4311241214141 is a deficient number, since it is larger than the sum of its proper divisors (1).

4311241214141 is an equidigital number, since it uses as much as digits as its factorization.

4311241214141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3072, while the sum is 29.

Adding to 4311241214141 its reverse (1414121421134), we get a palindrome (5725362635275).

The spelling of 4311241214141 in words is "four trillion, three hundred eleven billion, two hundred forty-one million, two hundred fourteen thousand, one hundred forty-one".