Base | Representation |
---|---|
bin | 101000001001101111… |
… | …100000100100111001 |
3 | 11010021121221112012012 |
4 | 220021233200210321 |
5 | 1201243424401410 |
6 | 31450023455305 |
7 | 3054245330354 |
oct | 501157404471 |
9 | 133247845165 |
10 | 43113122105 |
11 | 17314262829 |
12 | 84325b7535 |
13 | 40b1023251 |
14 | 212dc1d29b |
15 | 11c4e73605 |
hex | a09be0939 |
43113122105 has 8 divisors (see below), whose sum is σ = 51736878600. Its totient is φ = 34489742976.
The previous prime is 43113122099. The next prime is 43113122111. The reversal of 43113122105 is 50122131134.
It is an interprime number because it is at equal distance from previous prime (43113122099) and next prime (43113122111).
It can be written as a sum of positive squares in 4 ways, for example, as 21583135744 + 21529986361 = 146912^2 + 146731^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 43113122105 - 24 = 43113122089 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 332951 + ... + 443939.
It is an arithmetic number, because the mean of its divisors is an integer number (6467109825).
Almost surely, 243113122105 is an apocalyptic number.
It is an amenable number.
43113122105 is a deficient number, since it is larger than the sum of its proper divisors (8623756495).
43113122105 is a wasteful number, since it uses less digits than its factorization.
43113122105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 188683.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 43113122105 its reverse (50122131134), we get a palindrome (93235253239).
The spelling of 43113122105 in words is "forty-three billion, one hundred thirteen million, one hundred twenty-two thousand, one hundred five".
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