43114112021 has 2 divisors, whose sum is σ = 43114112022. Its totient is φ = 43114112020.

The previous prime is 43114112011. The next prime is 43114112023. The reversal of 43114112021 is 12021141134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33492660100 + 9621451921 = 183010^2 + 98089^2 .

It is a cyclic number.

It is not a de Polignac number, because 43114112021 - 2¹⁰ = 43114110997 is a prime.

Together with 43114112023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 43114111984 and 43114112002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43114112023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21557056010 + 21557056011.

It is an arithmetic number, because the mean of its divisors is an integer number (21557056011).

Almost surely, 2^43114112021 is an apocalyptic number.

It is an amenable number.

43114112021 is a deficient number, since it is larger than the sum of its proper divisors (1).

43114112021 is an equidigital number, since it uses as much as digits as its factorization.

43114112021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 43114112021 its reverse (12021141134), we get a palindrome (55135253155).

The spelling of 43114112021 in words is "forty-three billion, one hundred fourteen million, one hundred twelve thousand, twenty-one".