Base | Representation |
---|---|
bin | 1100100011000100100… |
… | …00100111010100000111 |
3 | 1112012212020212002220111 |
4 | 12101202100213110013 |
5 | 24030441141031403 |
6 | 530022043013451 |
7 | 43102116114166 |
oct | 6214220472407 |
9 | 1465766762814 |
10 | 431145252103 |
11 | 156936289275 |
12 | 6b68580a287 |
13 | 318700693b7 |
14 | 16c207693dd |
15 | b335d4656d |
hex | 6462427507 |
431145252103 has 2 divisors, whose sum is σ = 431145252104. Its totient is φ = 431145252102.
The previous prime is 431145252101. The next prime is 431145252113. The reversal of 431145252103 is 301252541134.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 431145252103 - 21 = 431145252101 is a prime.
Together with 431145252101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (431145252101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215572626051 + 215572626052.
It is an arithmetic number, because the mean of its divisors is an integer number (215572626052).
Almost surely, 2431145252103 is an apocalyptic number.
431145252103 is a deficient number, since it is larger than the sum of its proper divisors (1).
431145252103 is an equidigital number, since it uses as much as digits as its factorization.
431145252103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 431145252103 its reverse (301252541134), we get a palindrome (732397793237).
The spelling of 431145252103 in words is "four hundred thirty-one billion, one hundred forty-five million, two hundred fifty-two thousand, one hundred three".
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