Base | Representation |
---|---|
bin | 1100100011001100010… |
… | …01001000110111000101 |
3 | 1112020000210110000200210 |
4 | 12101212021020313011 |
5 | 24031104330314341 |
6 | 530032331230033 |
7 | 43103536635255 |
oct | 6214611106705 |
9 | 1466023400623 |
10 | 431210401221 |
11 | 15696a036816 |
12 | 6b6a35a8319 |
13 | 318806c9c82 |
14 | 16c29287965 |
15 | b33b914c16 |
hex | 6466248dc5 |
431210401221 has 4 divisors (see below), whose sum is σ = 574947201632. Its totient is φ = 287473600812.
The previous prime is 431210401169. The next prime is 431210401229. The reversal of 431210401221 is 122104012134.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 431210401221 - 210 = 431210400197 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (431210401229) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71868400201 + ... + 71868400206.
It is an arithmetic number, because the mean of its divisors is an integer number (143736800408).
Almost surely, 2431210401221 is an apocalyptic number.
It is an amenable number.
431210401221 is a deficient number, since it is larger than the sum of its proper divisors (143736800411).
431210401221 is a wasteful number, since it uses less digits than its factorization.
431210401221 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 143736800410.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 431210401221 its reverse (122104012134), we get a palindrome (553314413355).
The spelling of 431210401221 in words is "four hundred thirty-one billion, two hundred ten million, four hundred one thousand, two hundred twenty-one".
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