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4312134443171 is a prime number
BaseRepresentation
bin111110101111111111001…
…111011110000010100011
3120021020101001201022101102
4332233333033132002203
51031122222404140141
613100544530225015
7623353466000012
oct76577717360243
916236331638342
104312134443171
1114128475266a5
1259787912516b
1325382b8a1b19
1410c9cbc98a79
157727dae499b
hex3ebff3de0a3

4312134443171 has 2 divisors, whose sum is σ = 4312134443172. Its totient is φ = 4312134443170.

The previous prime is 4312134443161. The next prime is 4312134443173. The reversal of 4312134443171 is 1713444312134.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4312134443171 - 26 = 4312134443107 is a prime.

Together with 4312134443173, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (4312134443173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156067221585 + 2156067221586.

It is an arithmetic number, because the mean of its divisors is an integer number (2156067221586).

Almost surely, 24312134443171 is an apocalyptic number.

4312134443171 is a deficient number, since it is larger than the sum of its proper divisors (1).

4312134443171 is an equidigital number, since it uses as much as digits as its factorization.

4312134443171 is an evil number, because the sum of its binary digits is even.

The product of its digits is 96768, while the sum is 38.

The spelling of 4312134443171 in words is "four trillion, three hundred twelve billion, one hundred thirty-four million, four hundred forty-three thousand, one hundred seventy-one".