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4312134443173 is a prime number
BaseRepresentation
bin111110101111111111001…
…111011110000010100101
3120021020101001201022101111
4332233333033132002211
51031122222404140143
613100544530225021
7623353466000014
oct76577717360245
916236331638344
104312134443173
1114128475266a7
12597879125171
1325382b8a1b1b
1410c9cbc98a7b
157727dae499d
hex3ebff3de0a5

4312134443173 has 2 divisors, whose sum is σ = 4312134443174. Its totient is φ = 4312134443172.

The previous prime is 4312134443171. The next prime is 4312134443209. The reversal of 4312134443173 is 3713444312134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2304633682404 + 2007500760769 = 1518102^2 + 1416863^2 .

It is a cyclic number.

It is not a de Polignac number, because 4312134443173 - 21 = 4312134443171 is a prime.

Together with 4312134443171, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4312134443171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2156067221586 + 2156067221587.

It is an arithmetic number, because the mean of its divisors is an integer number (2156067221587).

Almost surely, 24312134443173 is an apocalyptic number.

It is an amenable number.

4312134443173 is a deficient number, since it is larger than the sum of its proper divisors (1).

4312134443173 is an equidigital number, since it uses as much as digits as its factorization.

4312134443173 is an evil number, because the sum of its binary digits is even.

The product of its digits is 290304, while the sum is 40.

The spelling of 4312134443173 in words is "four trillion, three hundred twelve billion, one hundred thirty-four million, four hundred forty-three thousand, one hundred seventy-three".