Base | Representation |
---|---|
bin | 101000001010010001… |
… | …011010100110101101 |
3 | 11010022020200002211112 |
4 | 220022101122212231 |
5 | 1201303213314131 |
6 | 31450542201405 |
7 | 3054414020231 |
oct | 501221324655 |
9 | 133266602745 |
10 | 43122010541 |
11 | 17319283845 |
12 | 8435583265 |
13 | 40b2b15b8c |
14 | 21310945c1 |
15 | 11c5b2c02b |
hex | a0a45a9ad |
43122010541 has 2 divisors, whose sum is σ = 43122010542. Its totient is φ = 43122010540.
The previous prime is 43122010523. The next prime is 43122010553. The reversal of 43122010541 is 14501022134.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42086522500 + 1035488041 = 205150^2 + 32179^2 .
It is a cyclic number.
It is not a de Polignac number, because 43122010541 - 222 = 43117816237 is a prime.
It is a super-2 number, since 2×431220105412 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43122010441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21561005270 + 21561005271.
It is an arithmetic number, because the mean of its divisors is an integer number (21561005271).
Almost surely, 243122010541 is an apocalyptic number.
It is an amenable number.
43122010541 is a deficient number, since it is larger than the sum of its proper divisors (1).
43122010541 is an equidigital number, since it uses as much as digits as its factorization.
43122010541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 43122010541 its reverse (14501022134), we get a palindrome (57623032675).
The spelling of 43122010541 in words is "forty-three billion, one hundred twenty-two million, ten thousand, five hundred forty-one".
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