Base | Representation |
---|---|
bin | 111110110000001111010… |
… | …011110010010011100101 |
3 | 120021021001211221201211221 |
4 | 332300033103302103211 |
5 | 1031123300411311323 |
6 | 13101031400100341 |
7 | 623363251165525 |
oct | 76601723622345 |
9 | 16237054851757 |
10 | 4312404010213 |
11 | 1412975704382 |
12 | 5979334646b1 |
13 | 2538726a5850 |
14 | 10ca159c9685 |
15 | 772975e155d |
hex | 3ec0f4f24e5 |
4312404010213 has 16 divisors (see below), whose sum is σ = 4847175196416. Its totient is φ = 3806720311680.
The previous prime is 4312404010171. The next prime is 4312404010279. The reversal of 4312404010213 is 3120104042134.
It is not a de Polignac number, because 4312404010213 - 29 = 4312404009701 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4312404016213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 393433 + ... + 2963038.
It is an arithmetic number, because the mean of its divisors is an integer number (302948449776).
Almost surely, 24312404010213 is an apocalyptic number.
It is an amenable number.
4312404010213 is a deficient number, since it is larger than the sum of its proper divisors (534771186203).
4312404010213 is a wasteful number, since it uses less digits than its factorization.
4312404010213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3360804.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4312404010213 its reverse (3120104042134), we get a palindrome (7432508052347).
The spelling of 4312404010213 in words is "four trillion, three hundred twelve billion, four hundred four million, ten thousand, two hundred thirteen".
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