Base | Representation |
---|---|
bin | 111110110000010000011… |
… | …000011111100011010010 |
3 | 120021021010002211210110100 |
4 | 332300100120133203102 |
5 | 1031123320014140310 |
6 | 13101033242113230 |
7 | 623363560242213 |
oct | 76602030374322 |
9 | 16237102753410 |
10 | 4312422021330 |
11 | 14129848963a5 |
12 | 5979394ab816 |
13 | 253876340907 |
14 | 10ca1815740a |
15 | 77298e9cec0 |
hex | 3ec1061f8d2 |
4312422021330 has 48 divisors (see below), whose sum is σ = 11802418168320. Its totient is φ = 1089453983904.
The previous prime is 4312422021287. The next prime is 4312422021361. The reversal of 4312422021330 is 331202242134.
4312422021330 is a `hidden beast` number, since 4 + 3 + 124 + 2 + 202 + 1 + 330 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 4312422021294 and 4312422021303.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1260940402 + ... + 1260943821.
It is an arithmetic number, because the mean of its divisors is an integer number (245883711840).
Almost surely, 24312422021330 is an apocalyptic number.
4312422021330 is an abundant number, since it is smaller than the sum of its proper divisors (7489996146990).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4312422021330 is a wasteful number, since it uses less digits than its factorization.
4312422021330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2521884255 (or 2521884252 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 4312422021330 its reverse (331202242134), we get a palindrome (4643624263464).
The spelling of 4312422021330 in words is "four trillion, three hundred twelve billion, four hundred twenty-two million, twenty-one thousand, three hundred thirty".
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