Base | Representation |
---|---|
bin | 101000001010111000… |
… | …000011001010001001 |
3 | 11010022221201122021002 |
4 | 220022320003022021 |
5 | 1201313311404441 |
6 | 31451543224345 |
7 | 3054566060552 |
oct | 501270031211 |
9 | 133287648232 |
10 | 43132138121 |
11 | 17323a70846 |
12 | 8438a480b5 |
13 | 40b4c50827 |
14 | 213256d329 |
15 | 11c697cb9b |
hex | a0ae03289 |
43132138121 has 2 divisors, whose sum is σ = 43132138122. Its totient is φ = 43132138120.
The previous prime is 43132138109. The next prime is 43132138123. The reversal of 43132138121 is 12183123134.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31803728896 + 11328409225 = 178336^2 + 106435^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43132138121 is a prime.
Together with 43132138123, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (43132138123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21566069060 + 21566069061.
It is an arithmetic number, because the mean of its divisors is an integer number (21566069061).
Almost surely, 243132138121 is an apocalyptic number.
It is an amenable number.
43132138121 is a deficient number, since it is larger than the sum of its proper divisors (1).
43132138121 is an equidigital number, since it uses as much as digits as its factorization.
43132138121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3456, while the sum is 29.
The spelling of 43132138121 in words is "forty-three billion, one hundred thirty-two million, one hundred thirty-eight thousand, one hundred twenty-one".
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