Base | Representation |
---|---|
bin | 101000001010111001… |
… | …000011100110111001 |
3 | 11010022222020001101021 |
4 | 220022321003212321 |
5 | 1201313343331410 |
6 | 31451553022441 |
7 | 3054601240312 |
oct | 501271034671 |
9 | 133288201337 |
10 | 43132402105 |
11 | 17324131111 |
12 | 8438b54a21 |
13 | 40b5013a30 |
14 | 21325db609 |
15 | 11c69d0eda |
hex | a0ae439b9 |
43132402105 has 16 divisors (see below), whose sum is σ = 55745464320. Its totient is φ = 31848689088.
The previous prime is 43132402069. The next prime is 43132402121. The reversal of 43132402105 is 50120423134.
It is a cyclic number.
It is not a de Polignac number, because 43132402105 - 217 = 43132271033 is a prime.
It is a super-2 number, since 2×431324021052 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 43132402105.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 895836 + ... + 942754.
It is an arithmetic number, because the mean of its divisors is an integer number (3484091520).
Almost surely, 243132402105 is an apocalyptic number.
It is an amenable number.
43132402105 is a deficient number, since it is larger than the sum of its proper divisors (12613062215).
43132402105 is a wasteful number, since it uses less digits than its factorization.
43132402105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61080.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 43132402105 its reverse (50120423134), we get a palindrome (93252825239).
The spelling of 43132402105 in words is "forty-three billion, one hundred thirty-two million, four hundred two thousand, one hundred five".
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