Base | Representation |
---|---|
bin | 1100100011011011111… |
… | …11111010010101001101 |
3 | 1112020100222110002211021 |
4 | 12101231333322111031 |
5 | 24031342100401031 |
6 | 530053400154141 |
7 | 43110030130546 |
oct | 6215577722515 |
9 | 1466328402737 |
10 | 431342200141 |
11 | 156a27477246 |
12 | 6b71b768951 |
13 | 318a1ac54b8 |
14 | 16c3c9954cd |
15 | b34829b511 |
hex | 646dffa54d |
431342200141 has 2 divisors, whose sum is σ = 431342200142. Its totient is φ = 431342200140.
The previous prime is 431342200139. The next prime is 431342200241. The reversal of 431342200141 is 141002243134.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 300693206025 + 130648994116 = 548355^2 + 361454^2 .
It is a cyclic number.
It is not a de Polignac number, because 431342200141 - 21 = 431342200139 is a prime.
Together with 431342200139, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (431342200111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215671100070 + 215671100071.
It is an arithmetic number, because the mean of its divisors is an integer number (215671100071).
Almost surely, 2431342200141 is an apocalyptic number.
It is an amenable number.
431342200141 is a deficient number, since it is larger than the sum of its proper divisors (1).
431342200141 is an equidigital number, since it uses as much as digits as its factorization.
431342200141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 431342200141 its reverse (141002243134), we get a palindrome (572344443275).
The spelling of 431342200141 in words is "four hundred thirty-one billion, three hundred forty-two million, two hundred thousand, one hundred forty-one".
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