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43140002513 is a prime number
BaseRepresentation
bin101000001011010110…
…000011001011010001
311010100111112012011212
4220023112003023101
51201322320040023
631452423545505
73055022654036
oct501326031321
9133314465155
1043140002513
1117328452443
12843b5bb295
1340b677530a
14213361938d
1511c74d2e78
hexa0b5832d1

43140002513 has 2 divisors, whose sum is σ = 43140002514. Its totient is φ = 43140002512.

The previous prime is 43140002501. The next prime is 43140002527. The reversal of 43140002513 is 31520004134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 41329670209 + 1810332304 = 203297^2 + 42548^2 .

It is a cyclic number.

It is not a de Polignac number, because 43140002513 - 212 = 43139998417 is a prime.

It is a super-2 number, since 2×431400025132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (43140002533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21570001256 + 21570001257.

It is an arithmetic number, because the mean of its divisors is an integer number (21570001257).

Almost surely, 243140002513 is an apocalyptic number.

It is an amenable number.

43140002513 is a deficient number, since it is larger than the sum of its proper divisors (1).

43140002513 is an equidigital number, since it uses as much as digits as its factorization.

43140002513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 43140002513 its reverse (31520004134), we get a palindrome (74660006647).

The spelling of 43140002513 in words is "forty-three billion, one hundred forty million, two thousand, five hundred thirteen".