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43140002533 is a prime number
BaseRepresentation
bin101000001011010110…
…000011001011100101
311010100111112012012121
4220023112003023211
51201322320040113
631452423545541
73055022654065
oct501326031345
9133314465177
1043140002533
1117328452461
12843b5bb2b1
1340b6775324
1421336193a5
1511c74d2e8d
hexa0b5832e5

43140002533 has 2 divisors, whose sum is σ = 43140002534. Its totient is φ = 43140002532.

The previous prime is 43140002527. The next prime is 43140002551. The reversal of 43140002533 is 33520004134.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 43081983844 + 58018689 = 207562^2 + 7617^2 .

It is a cyclic number.

It is not a de Polignac number, because 43140002533 - 25 = 43140002501 is a prime.

It is a super-2 number, since 2×431400025332 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43140002498 and 43140002507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43140002513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21570001266 + 21570001267.

It is an arithmetic number, because the mean of its divisors is an integer number (21570001267).

Almost surely, 243140002533 is an apocalyptic number.

It is an amenable number.

43140002533 is a deficient number, since it is larger than the sum of its proper divisors (1).

43140002533 is an equidigital number, since it uses as much as digits as its factorization.

43140002533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 43140002533 its reverse (33520004134), we get a palindrome (76660006667).

The spelling of 43140002533 in words is "forty-three billion, one hundred forty million, two thousand, five hundred thirty-three".