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43140014551 = 149289530299
BaseRepresentation
bin101000001011010110…
…000110000111010111
311010100111112210200201
4220023112012013113
51201322320431201
631452424121331
73055023034114
oct501326060727
9133314483621
1043140014551
1117328460497
12843b606247
1340b677a93a
14213361d90b
1511c74d6801
hexa0b5861d7

43140014551 has 4 divisors (see below), whose sum is σ = 43429545000. Its totient is φ = 42850484104.

The previous prime is 43140014531. The next prime is 43140014587. The reversal of 43140014551 is 15541004134.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 43140014551 - 221 = 43137917399 is a prime.

It is a super-2 number, since 2×431400145512 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43140014531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144765001 + ... + 144765298.

It is an arithmetic number, because the mean of its divisors is an integer number (10857386250).

Almost surely, 243140014551 is an apocalyptic number.

43140014551 is a deficient number, since it is larger than the sum of its proper divisors (289530449).

43140014551 is a wasteful number, since it uses less digits than its factorization.

43140014551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 289530448.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 43140014551 its reverse (15541004134), we get a palindrome (58681018685).

The spelling of 43140014551 in words is "forty-three billion, one hundred forty million, fourteen thousand, five hundred fifty-one".

Divisors: 1 149 289530299 43140014551