Base | Representation |
---|---|
bin | 111110110001110001000… |
… | …100001111010111011111 |
3 | 120021102022011002000222022 |
4 | 332301301010033113133 |
5 | 1031140130242231421 |
6 | 13101502225010355 |
7 | 623452014555542 |
oct | 76616104172737 |
9 | 16242264060868 |
10 | 4314044102111 |
11 | 1413637479727 |
12 | 5981107839bb |
13 | 253a74407c23 |
14 | 10cb2d758859 |
15 | 773415ae7ab |
hex | 3ec7110f5df |
4314044102111 has 2 divisors, whose sum is σ = 4314044102112. Its totient is φ = 4314044102110.
The previous prime is 4314044102087. The next prime is 4314044102129. The reversal of 4314044102111 is 1112014404134.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4314044102111 - 230 = 4312970360287 is a prime.
It is a super-2 number, since 2×43140441021112 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4314044102191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2157022051055 + 2157022051056.
It is an arithmetic number, because the mean of its divisors is an integer number (2157022051056).
Almost surely, 24314044102111 is an apocalyptic number.
4314044102111 is a deficient number, since it is larger than the sum of its proper divisors (1).
4314044102111 is an equidigital number, since it uses as much as digits as its factorization.
4314044102111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 26.
Adding to 4314044102111 its reverse (1112014404134), we get a palindrome (5426058506245).
The spelling of 4314044102111 in words is "four trillion, three hundred fourteen billion, forty-four million, one hundred two thousand, one hundred eleven".
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