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4314113332469 is a prime number
BaseRepresentation
bin111110110001110101001…
…100010101010011110101
3120021102110222100022011122
4332301311030111103311
51031140301003114334
613101513140513325
7623453515165403
oct76616514252365
916242428308148
104314113332469
1114136725644a6
1259812b9ab845
13253a85867335
1410cb38a1a473
15773476d732e
hex3ec753154f5

4314113332469 has 2 divisors, whose sum is σ = 4314113332470. Its totient is φ = 4314113332468.

The previous prime is 4314113332369. The next prime is 4314113332519. The reversal of 4314113332469 is 9642333114134.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3766172879569 + 547940452900 = 1940663^2 + 740230^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4314113332469 is a prime.

It is a super-3 number, since 3×43141133324693 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4314113332369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2157056666234 + 2157056666235.

It is an arithmetic number, because the mean of its divisors is an integer number (2157056666235).

Almost surely, 24314113332469 is an apocalyptic number.

It is an amenable number.

4314113332469 is a deficient number, since it is larger than the sum of its proper divisors (1).

4314113332469 is an equidigital number, since it uses as much as digits as its factorization.

4314113332469 is an evil number, because the sum of its binary digits is even.

The product of its digits is 559872, while the sum is 44.

The spelling of 4314113332469 in words is "four trillion, three hundred fourteen billion, one hundred thirteen million, three hundred thirty-two thousand, four hundred sixty-nine".