Base | Representation |
---|---|
bin | 101000001011100001… |
… | …111101000001010111 |
3 | 11010100201101201201121 |
4 | 220023201331001113 |
5 | 1201324114414111 |
6 | 31453014504411 |
7 | 3055061331541 |
oct | 501341750127 |
9 | 133321351647 |
10 | 43143123031 |
11 | 1732a193988 |
12 | 8440665107 |
13 | 40b72c8788 |
14 | 2133bcc691 |
15 | 11c78ec871 |
hex | a0b87d057 |
43143123031 has 2 divisors, whose sum is σ = 43143123032. Its totient is φ = 43143123030.
The previous prime is 43143123019. The next prime is 43143123077. The reversal of 43143123031 is 13032134134.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 43143123031 - 235 = 8783384663 is a prime.
It is a super-2 number, since 2×431431230312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43143122987 and 43143123005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43143123731) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21571561515 + 21571561516.
It is an arithmetic number, because the mean of its divisors is an integer number (21571561516).
Almost surely, 243143123031 is an apocalyptic number.
43143123031 is a deficient number, since it is larger than the sum of its proper divisors (1).
43143123031 is an equidigital number, since it uses as much as digits as its factorization.
43143123031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 43143123031 its reverse (13032134134), we get a palindrome (56175257165).
The spelling of 43143123031 in words is "forty-three billion, one hundred forty-three million, one hundred twenty-three thousand, thirty-one".
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