43144013131 has 4 divisors (see below), whose sum is σ = 43145563264. Its totient is φ = 43142463000.

The previous prime is 43144013119. The next prime is 43144013179. The reversal of 43144013131 is 13131044134.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 43144013131 - 2²⁹ = 42607142219 is a prime.

It is a super-2 number, since 2×43144013131² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43144013096 and 43144013105.

It is not an unprimeable number, because it can be changed into a prime (43144016131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 732540 + ... + 789241.

It is an arithmetic number, because the mean of its divisors is an integer number (10786390816).

Almost surely, 2^43144013131 is an apocalyptic number.

43144013131 is a deficient number, since it is larger than the sum of its proper divisors (1550133).

43144013131 is a wasteful number, since it uses less digits than its factorization.

43144013131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1550132.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 43144013131 its reverse (13131044134), we get a palindrome (56275057265).

The spelling of 43144013131 in words is "forty-three billion, one hundred forty-four million, thirteen thousand, one hundred thirty-one".