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43144024143 = 3112118854061
BaseRepresentation
bin101000001011100101…
…011001000001001111
311010100210002111211010
4220023211121001033
51201324332233033
631453050100303
73055102103643
oct501345310117
9133323074733
1043144024143
111732a749a00
128440a1a693
1340b755298c
142133d84c23
1511c7a29863
hexa0b95904f

43144024143 has 12 divisors (see below), whose sum is σ = 63230360984. Its totient is φ = 26147893200.

The previous prime is 43144024129. The next prime is 43144024171. The reversal of 43144024143 is 34142044134.

It is not a de Polignac number, because 43144024143 - 210 = 43144023119 is a prime.

It is a super-2 number, since 2×431440241432 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 43144024143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43144024643) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 59426668 + ... + 59427393.

Almost surely, 243144024143 is an apocalyptic number.

43144024143 is a deficient number, since it is larger than the sum of its proper divisors (20086336841).

43144024143 is a wasteful number, since it uses less digits than its factorization.

43144024143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 118854086 (or 118854075 counting only the distinct ones).

The product of its (nonzero) digits is 18432, while the sum is 30.

Adding to 43144024143 its reverse (34142044134), we get a palindrome (77286068277).

The spelling of 43144024143 in words is "forty-three billion, one hundred forty-four million, twenty-four thousand, one hundred forty-three".

Divisors: 1 3 11 33 121 363 118854061 356562183 1307394671 3922184013 14381341381 43144024143