Search a number
-
+
43144143311132 = 2254939119632713
BaseRepresentation
bin10011100111101010001110…
…10101100001000100011100
312122202112120112021011212122
421303311013111201010130
521123333201141424012
6231432051255122112
712042030043164323
oct1163650725410434
9178675515234778
1043144143311132
1112824368151966
124a0975a373338
131b0c6241a7536
14a9228adbb0ba
154ec428cb4e72
hex273d4756111c

43144143311132 has 12 divisors (see below), whose sum is σ = 75502392069216. Its totient is φ = 21572031291360.

The previous prime is 43144143311117. The next prime is 43144143311183. The reversal of 43144143311132 is 23111334144134.

It is a happy number.

It is a super-2 number, since 2×431441433111322 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 43144143311092 and 43144143311101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7618793 + ... + 12013920.

It is an arithmetic number, because the mean of its divisors is an integer number (6291866005768).

Almost surely, 243144143311132 is an apocalyptic number.

It is an amenable number.

43144143311132 is a deficient number, since it is larger than the sum of its proper divisors (32358248758084).

43144143311132 is a wasteful number, since it uses less digits than its factorization.

43144143311132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20182108 (or 20182106 counting only the distinct ones).

The product of its digits is 41472, while the sum is 35.

Adding to 43144143311132 its reverse (23111334144134), we get a palindrome (66255477455266).

The spelling of 43144143311132 in words is "forty-three trillion, one hundred forty-four billion, one hundred forty-three million, three hundred eleven thousand, one hundred thirty-two".

Divisors: 1 2 4 549391 1098782 2197564 19632713 39265426 78530852 10786035827783 21572071655566 43144143311132