Base | Representation |
---|---|
bin | 10011100111101010001110… |
… | …10101100001000100011100 |
3 | 12122202112120112021011212122 |
4 | 21303311013111201010130 |
5 | 21123333201141424012 |
6 | 231432051255122112 |
7 | 12042030043164323 |
oct | 1163650725410434 |
9 | 178675515234778 |
10 | 43144143311132 |
11 | 12824368151966 |
12 | 4a0975a373338 |
13 | 1b0c6241a7536 |
14 | a9228adbb0ba |
15 | 4ec428cb4e72 |
hex | 273d4756111c |
43144143311132 has 12 divisors (see below), whose sum is σ = 75502392069216. Its totient is φ = 21572031291360.
The previous prime is 43144143311117. The next prime is 43144143311183. The reversal of 43144143311132 is 23111334144134.
It is a happy number.
It is a super-2 number, since 2×431441433111322 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43144143311092 and 43144143311101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7618793 + ... + 12013920.
It is an arithmetic number, because the mean of its divisors is an integer number (6291866005768).
Almost surely, 243144143311132 is an apocalyptic number.
It is an amenable number.
43144143311132 is a deficient number, since it is larger than the sum of its proper divisors (32358248758084).
43144143311132 is a wasteful number, since it uses less digits than its factorization.
43144143311132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20182108 (or 20182106 counting only the distinct ones).
The product of its digits is 41472, while the sum is 35.
Adding to 43144143311132 its reverse (23111334144134), we get a palindrome (66255477455266).
The spelling of 43144143311132 in words is "forty-three trillion, one hundred forty-four billion, one hundred forty-three million, three hundred eleven thousand, one hundred thirty-two".
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