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4315352133551 is a prime number
BaseRepresentation
bin111110110010111111000…
…001111110111110101111
3120021112200022100220210012
4332302333001332332233
51031200320121233201
613102240112403435
7623526306626354
oct76627701767657
916245608326705
104315352133551
111414148862048
1259841684657b
13253c223c5724
1410cc1536a62b
15773bb3395bb
hex3ecbf07efaf

4315352133551 has 2 divisors, whose sum is σ = 4315352133552. Its totient is φ = 4315352133550.

The previous prime is 4315352133487. The next prime is 4315352133553. The reversal of 4315352133551 is 1553312535134.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4315352133551 - 26 = 4315352133487 is a prime.

It is a Sophie Germain prime.

Together with 4315352133553, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 4315352133499 and 4315352133508.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4315352133553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2157676066775 + 2157676066776.

It is an arithmetic number, because the mean of its divisors is an integer number (2157676066776).

Almost surely, 24315352133551 is an apocalyptic number.

4315352133551 is a deficient number, since it is larger than the sum of its proper divisors (1).

4315352133551 is an equidigital number, since it uses as much as digits as its factorization.

4315352133551 is an evil number, because the sum of its binary digits is even.

The product of its digits is 405000, while the sum is 41.

Adding to 4315352133551 its reverse (1553312535134), we get a palindrome (5868664668685).

The spelling of 4315352133551 in words is "four trillion, three hundred fifteen billion, three hundred fifty-two million, one hundred thirty-three thousand, five hundred fifty-one".