Base | Representation |
---|---|
bin | 101000001100011110… |
… | …001000000101110101 |
3 | 11010101211002010120011 |
4 | 220030132020011311 |
5 | 1201342134201023 |
6 | 31454340540221 |
7 | 3055342400041 |
oct | 501436100565 |
9 | 133354063504 |
10 | 43158897013 |
11 | 17338088131 |
12 | 84459b1671 |
13 | 40ba65c4ab |
14 | 2135d37021 |
15 | 11c8eb650d |
hex | a0c788175 |
43158897013 has 4 divisors (see below), whose sum is σ = 43678883808. Its totient is φ = 42638910220.
The previous prime is 43158897007. The next prime is 43158897017. The reversal of 43158897013 is 31079885134.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31079885134 = 2 ⋅15539942567.
It is a cyclic number.
It is not a de Polignac number, because 43158897013 - 225 = 43125342581 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43158897017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 259993273 + ... + 259993438.
It is an arithmetic number, because the mean of its divisors is an integer number (10919720952).
Almost surely, 243158897013 is an apocalyptic number.
It is an amenable number.
43158897013 is a deficient number, since it is larger than the sum of its proper divisors (519986795).
43158897013 is an equidigital number, since it uses as much as digits as its factorization.
43158897013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 519986794.
The product of its (nonzero) digits is 725760, while the sum is 49.
The spelling of 43158897013 in words is "forty-three billion, one hundred fifty-eight million, eight hundred ninety-seven thousand, thirteen".
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