Base | Representation |
---|---|
bin | 111110111001010011001… |
… | …101000110101101000111 |
3 | 120022012011212211212021002 |
4 | 332321103031012231013 |
5 | 1031303212024402124 |
6 | 13105321023043515 |
7 | 624156325463606 |
oct | 76712315065507 |
9 | 16265155755232 |
10 | 4322133044039 |
11 | 14170084754a8 |
12 | 5997a974059b |
13 | 2547631bc4b5 |
14 | 10d299b75a3d |
15 | 776667c80ae |
hex | 3ee53346b47 |
4322133044039 has 2 divisors, whose sum is σ = 4322133044040. Its totient is φ = 4322133044038.
The previous prime is 4322133044017. The next prime is 4322133044041. The reversal of 4322133044039 is 9304403312234.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4322133044039 - 28 = 4322133043783 is a prime.
Together with 4322133044041, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 4322133043993 and 4322133044011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4322133044059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2161066522019 + 2161066522020.
It is an arithmetic number, because the mean of its divisors is an integer number (2161066522020).
Almost surely, 24322133044039 is an apocalyptic number.
4322133044039 is a deficient number, since it is larger than the sum of its proper divisors (1).
4322133044039 is an equidigital number, since it uses as much as digits as its factorization.
4322133044039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 186624, while the sum is 38.
The spelling of 4322133044039 in words is "four trillion, three hundred twenty-two billion, one hundred thirty-three million, forty-four thousand, thirty-nine".
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