Base | Representation |
---|---|
bin | 111110111011000010100… |
… | …000001111100011101101 |
3 | 120022101000000110220210221 |
4 | 332323002200033203231 |
5 | 1031321023041111023 |
6 | 13110230205331341 |
7 | 624253521251065 |
oct | 76730240174355 |
9 | 16271000426727 |
10 | 4324000332013 |
11 | 14178865085aa |
12 | 59a02ab66b51 |
13 | 2549a000b81b |
14 | 10d3d5b663a5 |
15 | 777256c385d |
hex | 3eec280f8ed |
4324000332013 has 2 divisors, whose sum is σ = 4324000332014. Its totient is φ = 4324000332012.
The previous prime is 4324000332007. The next prime is 4324000332023. The reversal of 4324000332013 is 3102330004234.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3286254716809 + 1037745615204 = 1812803^2 + 1018698^2 .
It is a cyclic number.
It is not a de Polignac number, because 4324000332013 - 29 = 4324000331501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4324000332023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2162000166006 + 2162000166007.
It is an arithmetic number, because the mean of its divisors is an integer number (2162000166007).
Almost surely, 24324000332013 is an apocalyptic number.
It is an amenable number.
4324000332013 is a deficient number, since it is larger than the sum of its proper divisors (1).
4324000332013 is an equidigital number, since it uses as much as digits as its factorization.
4324000332013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 4324000332013 its reverse (3102330004234), we get a palindrome (7426330336247).
The spelling of 4324000332013 in words is "four trillion, three hundred twenty-four billion, three hundred thirty-two thousand, thirteen".
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