Base | Representation |
---|---|
bin | 111111000000111010101… |
… | …101110110001101010100 |
3 | 120022222021220020112212001 |
4 | 333000322231312031110 |
5 | 1031421434401201122 |
6 | 13113152401205044 |
7 | 624566112541441 |
oct | 77007255661524 |
9 | 16288256215761 |
10 | 4330312131412 |
11 | 141a525341943 |
12 | 59b2b0930784 |
13 | 255467876c77 |
14 | 10d83413a9c8 |
15 | 7799489b527 |
hex | 3f03ab76354 |
4330312131412 has 12 divisors (see below), whose sum is σ = 7579367177620. Its totient is φ = 2164778652096.
The previous prime is 4330312131403. The next prime is 4330312131433. The reversal of 4330312131412 is 2141312130334.
It can be written as a sum of positive squares in 2 ways, for example, as 1848691631556 + 2481620499856 = 1359666^2 + 1575316^2 .
It is a super-2 number, since 2×43303121314122 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94327587 + ... + 94373482.
Almost surely, 24330312131412 is an apocalyptic number.
It is an amenable number.
4330312131412 is a deficient number, since it is larger than the sum of its proper divisors (3249055046208).
4330312131412 is a wasteful number, since it uses less digits than its factorization.
4330312131412 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 188706810 (or 188706808 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 4330312131412 its reverse (2141312130334), we get a palindrome (6471624261746).
The spelling of 4330312131412 in words is "four trillion, three hundred thirty billion, three hundred twelve million, one hundred thirty-one thousand, four hundred twelve".
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