Base | Representation |
---|---|
bin | 111111000001100110001… |
… | …010010011011011010101 |
3 | 120100001011200202111020122 |
4 | 333001212022103123111 |
5 | 1031424432444331123 |
6 | 13113352555441325 |
7 | 624623143115144 |
oct | 77014612233325 |
9 | 16301150674218 |
10 | 4331041011413 |
11 | 141a869817206 |
12 | 59b474a56245 |
13 | 2555528885cc |
14 | 10d8a2c7175b |
15 | 779d8875bc8 |
hex | 3f0662936d5 |
4331041011413 has 8 divisors (see below), whose sum is σ = 4547073202368. Its totient is φ = 4117319325504.
The previous prime is 4331041011373. The next prime is 4331041011419. The reversal of 4331041011413 is 3141101401334.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 4331041011413 - 236 = 4262321534677 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4331041011419) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 577622420 + ... + 577629917.
It is an arithmetic number, because the mean of its divisors is an integer number (568384150296).
Almost surely, 24331041011413 is an apocalyptic number.
It is an amenable number.
4331041011413 is a deficient number, since it is larger than the sum of its proper divisors (216032190955).
4331041011413 is a wasteful number, since it uses less digits than its factorization.
4331041011413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1155252523.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 4331041011413 its reverse (3141101401334), we get a palindrome (7472142412747).
The spelling of 4331041011413 in words is "four trillion, three hundred thirty-one billion, forty-one million, eleven thousand, four hundred thirteen".
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