43311213140404 has 24 divisors (see below), whose sum is σ = 82708728764256. Its totient is φ = 19681275660000.

The previous prime is 43311213140389. The next prime is 43311213140543. The reversal of 43311213140404 is 40404131211334.

It is a super-2 number, since 2×43311213140404² (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 140829747 + ... + 141136954.

It is an arithmetic number, because the mean of its divisors is an integer number (3446197031844).

Almost surely, 2^{43311213140404} is an apocalyptic number.

43311213140404 is a gapful number since it is divisible by the number (44) formed by its first and last digit.

It is an amenable number.

43311213140404 is a deficient number, since it is larger than the sum of its proper divisors (39397515623852).

43311213140404 is a wasteful number, since it uses less digits than its factorization.

43311213140404 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 281970207 (or 281970205 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 43311213140404 its reverse (40404131211334), we get a palindrome (83715344351738).

The spelling of 43311213140404 in words is "forty-three trillion, three hundred eleven billion, two hundred thirteen million, one hundred forty thousand, four hundred four".