Base | Representation |
---|---|
bin | 1000000100010011… |
… | …11011000101101101 |
3 | 102011211202211212221 |
4 | 10002021323011231 |
5 | 32332231414203 |
6 | 1553434555341 |
7 | 212220636625 |
oct | 40211730555 |
9 | 12154684787 |
10 | 4331123053 |
11 | 1922895944 |
12 | a0a598b51 |
13 | 5403c870a |
14 | 2d1309885 |
15 | 1a5380abd |
hex | 10227b16d |
4331123053 has 2 divisors, whose sum is σ = 4331123054. Its totient is φ = 4331123052.
The previous prime is 4331123051. The next prime is 4331123113. The reversal of 4331123053 is 3503211334.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3728567844 + 602555209 = 61062^2 + 24547^2 .
It is a cyclic number.
It is not a de Polignac number, because 4331123053 - 21 = 4331123051 is a prime.
Together with 4331123051, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4331123051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165561526 + 2165561527.
It is an arithmetic number, because the mean of its divisors is an integer number (2165561527).
Almost surely, 24331123053 is an apocalyptic number.
It is an amenable number.
4331123053 is a deficient number, since it is larger than the sum of its proper divisors (1).
4331123053 is an equidigital number, since it uses as much as digits as its factorization.
4331123053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 25.
The square root of 4331123053 is about 65811.2684348205. The cubic root of 4331123053 is about 1630.0471780541.
Adding to 4331123053 its reverse (3503211334), we get a palindrome (7834334387).
The spelling of 4331123053 in words is "four billion, three hundred thirty-one million, one hundred twenty-three thousand, fifty-three".
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