Base | Representation |
---|---|
bin | 10011101100100011011100… |
… | …11001101010011101011100 |
3 | 12200100121121211022201111121 |
4 | 21312101232121222131130 |
5 | 21134112043410343030 |
6 | 232041221432500324 |
7 | 12060132142145215 |
oct | 1166215631523534 |
9 | 180317554281447 |
10 | 43312302434140 |
11 | 1288970a635993 |
12 | 4a3626a54a6a4 |
13 | 1b2244292b79c |
14 | a9a48037a40c |
15 | 5019bbbd047a |
hex | 27646e66a75c |
43312302434140 has 12 divisors (see below), whose sum is σ = 90955835111736. Its totient is φ = 17324920973648.
The previous prime is 43312302434131. The next prime is 43312302434197. The reversal of 43312302434140 is 4143420321334.
It is a super-3 number, since 3×433123024341403 (a number of 42 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43312302434096 and 43312302434105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1082807560834 + ... + 1082807560873.
It is an arithmetic number, because the mean of its divisors is an integer number (7579652925978).
Almost surely, 243312302434140 is an apocalyptic number.
It is an amenable number.
43312302434140 is an abundant number, since it is smaller than the sum of its proper divisors (47643532677596).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
43312302434140 is a wasteful number, since it uses less digits than its factorization.
43312302434140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2165615121716 (or 2165615121714 counting only the distinct ones).
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 43312302434140 its reverse (4143420321334), we get a palindrome (47455722755474).
The spelling of 43312302434140 in words is "forty-three trillion, three hundred twelve billion, three hundred two million, four hundred thirty-four thousand, one hundred forty".
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