Base | Representation |
---|---|
bin | 1100100110110001001… |
… | …00100110010001101101 |
3 | 1112101222120220000120112 |
4 | 12103120210212101231 |
5 | 24044022312432341 |
6 | 530551031225405 |
7 | 43202240654603 |
oct | 6233044462155 |
9 | 1471876800515 |
10 | 433130202221 |
11 | 157764786712 |
12 | 6bb3a518265 |
13 | 31ac83744b2 |
14 | 16d6c227873 |
15 | b400234aeb |
hex | 64d892646d |
433130202221 has 2 divisors, whose sum is σ = 433130202222. Its totient is φ = 433130202220.
The previous prime is 433130202203. The next prime is 433130202269. The reversal of 433130202221 is 122202031334.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 432904782025 + 225420196 = 657955^2 + 15014^2 .
It is a cyclic number.
It is not a de Polignac number, because 433130202221 - 226 = 433063093357 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (433130201221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216565101110 + 216565101111.
It is an arithmetic number, because the mean of its divisors is an integer number (216565101111).
Almost surely, 2433130202221 is an apocalyptic number.
It is an amenable number.
433130202221 is a deficient number, since it is larger than the sum of its proper divisors (1).
433130202221 is an equidigital number, since it uses as much as digits as its factorization.
433130202221 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 433130202221 its reverse (122202031334), we get a palindrome (555332233555).
The spelling of 433130202221 in words is "four hundred thirty-three billion, one hundred thirty million, two hundred two thousand, two hundred twenty-one".
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