Base | Representation |
---|---|
bin | 101000010101101010… |
… | …110101011010101100 |
3 | 11010210120110201111001 |
4 | 220111222311122230 |
5 | 1202201141121330 |
6 | 31521532410044 |
7 | 3062225216032 |
oct | 502552653254 |
9 | 133716421431 |
10 | 43313223340 |
11 | 17407204852 |
12 | 8489616924 |
13 | 411361464a |
14 | 214c62a552 |
15 | 11d77ec9ca |
hex | a15ab56ac |
43313223340 has 48 divisors (see below), whose sum is σ = 92753466624. Its totient is φ = 16985707200.
The previous prime is 43313223319. The next prime is 43313223377. The reversal of 43313223340 is 4332231334.
It is a happy number.
43313223340 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×433132233402 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43313223299 and 43313223308.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 206145 + ... + 359335.
It is an arithmetic number, because the mean of its divisors is an integer number (1932363888).
Almost surely, 243313223340 is an apocalyptic number.
It is an amenable number.
43313223340 is an abundant number, since it is smaller than the sum of its proper divisors (49440243284).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
43313223340 is a wasteful number, since it uses less digits than its factorization.
43313223340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 153478 (or 153476 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 28.
Adding to 43313223340 its reverse (4332231334), we get a palindrome (47645454674).
The spelling of 43313223340 in words is "forty-three billion, three hundred thirteen million, two hundred twenty-three thousand, three hundred forty".
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