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433140121 is a prime number
BaseRepresentation
bin11001110100010…
…011000110011001
31010012000210112201
4121310103012121
51341340440441
6110551410201
713506426121
oct3164230631
91105023481
10433140121
11202550647
12101083961
136b97593b
144174dc81
152805cc31
hex19d13199

433140121 has 2 divisors, whose sum is σ = 433140122. Its totient is φ = 433140120.

The previous prime is 433140119. The next prime is 433140133. The reversal of 433140121 is 121041334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 421850521 + 11289600 = 20539^2 + 3360^2 .

It is a cyclic number.

It is not a de Polignac number, because 433140121 - 21 = 433140119 is a prime.

It is a super-2 number, since 2×4331401212 = 375220728839789282, which contains 22 as substring.

Together with 433140119, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (433110121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 216570060 + 216570061.

It is an arithmetic number, because the mean of its divisors is an integer number (216570061).

Almost surely, 2433140121 is an apocalyptic number.

It is an amenable number.

433140121 is a deficient number, since it is larger than the sum of its proper divisors (1).

433140121 is an equidigital number, since it uses as much as digits as its factorization.

433140121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 433140121 is about 20812.0186671068. The cubic root of 433140121 is about 756.6170746628.

Adding to 433140121 its reverse (121041334), we get a palindrome (554181455).

The spelling of 433140121 in words is "four hundred thirty-three million, one hundred forty thousand, one hundred twenty-one".