Base | Representation |
---|---|
bin | 111111000001111011101… |
… | …001001110101100000011 |
3 | 120100002002210222011022200 |
4 | 333001323221032230003 |
5 | 1031431202232040003 |
6 | 13113452433004243 |
7 | 624635110525311 |
oct | 77017351165403 |
9 | 16302083864280 |
10 | 4331401440003 |
11 | 141aa34214580 |
12 | 59b5556b3683 |
13 | 2555ac453471 |
14 | 10d8d8a950b1 |
15 | 77a0a31e6a3 |
hex | 3f07ba4eb03 |
4331401440003 has 48 divisors (see below), whose sum is σ = 6871468032000. Its totient is φ = 2607368198400.
The previous prime is 4331401439977. The next prime is 4331401440049. The reversal of 4331401440003 is 3000441041334.
It is not a de Polignac number, because 4331401440003 - 28 = 4331401439747 is a prime.
It is a super-2 number, since 2×43314014400032 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (4331401442003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 8900998 + ... + 9374996.
It is an arithmetic number, because the mean of its divisors is an integer number (143155584000).
Almost surely, 24331401440003 is an apocalyptic number.
4331401440003 is a deficient number, since it is larger than the sum of its proper divisors (2540066591997).
4331401440003 is a wasteful number, since it uses less digits than its factorization.
4331401440003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 474640 (or 474637 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 4331401440003 its reverse (3000441041334), we get a palindrome (7331842481337).
The spelling of 4331401440003 in words is "four trillion, three hundred thirty-one billion, four hundred one million, four hundred forty thousand, three".
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