Base | Representation |
---|---|
bin | 101000010101101110… |
… | …111101010101010101 |
3 | 11010210122111122100010 |
4 | 220111232331111111 |
5 | 1202201430214331 |
6 | 31522011510433 |
7 | 3062240340450 |
oct | 502556752525 |
9 | 133718448303 |
10 | 43314304341 |
11 | 17407882a40 |
12 | 8489a58419 |
13 | 41139026a9 |
14 | 214c82c497 |
15 | 11d7962e46 |
hex | a15bbd555 |
43314304341 has 32 divisors (see below), whose sum is σ = 72216787968. Its totient is φ = 22434128640.
The previous prime is 43314304337. The next prime is 43314304349. The reversal of 43314304341 is 14340341334.
It is not a de Polignac number, because 43314304341 - 22 = 43314304337 is a prime.
It is a super-2 number, since 2×433143043412 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43314304299 and 43314304308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43314304349) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 200355 + ... + 356048.
It is an arithmetic number, because the mean of its divisors is an integer number (2256774624).
Almost surely, 243314304341 is an apocalyptic number.
It is an amenable number.
43314304341 is a deficient number, since it is larger than the sum of its proper divisors (28902483627).
43314304341 is a wasteful number, since it uses less digits than its factorization.
43314304341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 556761.
The product of its (nonzero) digits is 20736, while the sum is 30.
Adding to 43314304341 its reverse (14340341334), we get a palindrome (57654645675).
The spelling of 43314304341 in words is "forty-three billion, three hundred fourteen million, three hundred four thousand, three hundred forty-one".
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