Search a number
-
+
4331702066047 is a prime number
BaseRepresentation
bin111111000010001101100…
…100000001101101111111
3120100002212202122112201121
4333002031210001231333
51031432311212103142
613113542332251411
7624645421023136
oct77021544015577
916302782575647
104331702066047
111420078986354
1259b61a310b67
132556298101b5
1410d92698c91d
1577a26903c67
hex3f08d901b7f

4331702066047 has 2 divisors, whose sum is σ = 4331702066048. Its totient is φ = 4331702066046.

The previous prime is 4331702066017. The next prime is 4331702066071. The reversal of 4331702066047 is 7406602071334.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4331702066047 - 223 = 4331693677439 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4331702065994 and 4331702066012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4331702066017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2165851033023 + 2165851033024.

It is an arithmetic number, because the mean of its divisors is an integer number (2165851033024).

Almost surely, 24331702066047 is an apocalyptic number.

4331702066047 is a deficient number, since it is larger than the sum of its proper divisors (1).

4331702066047 is an equidigital number, since it uses as much as digits as its factorization.

4331702066047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 508032, while the sum is 43.

The spelling of 4331702066047 in words is "four trillion, three hundred thirty-one billion, seven hundred two million, sixty-six thousand, forty-seven".