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43320432041113 is a prime number
BaseRepresentation
bin10011101100110010100101…
…11101101001110010011001
312200101101121101121112202011
421312121102331221302121
521134230221100303423
6232045044242305521
712060540455521243
oct1166312275516231
9180341541545664
1043320432041113
1112892101586a37
124a379590582a1
131b23139c80506
14a9aa11d41093
15501ce577cb0d
hex276652f69c99

43320432041113 has 2 divisors, whose sum is σ = 43320432041114. Its totient is φ = 43320432041112.

The previous prime is 43320432041111. The next prime is 43320432041129. The reversal of 43320432041113 is 31114023402334.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23221681556544 + 20098750484569 = 4818888^2 + 4483163^2 .

It is a cyclic number.

It is not a de Polignac number, because 43320432041113 - 21 = 43320432041111 is a prime.

Together with 43320432041111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (43320432041111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21660216020556 + 21660216020557.

It is an arithmetic number, because the mean of its divisors is an integer number (21660216020557).

Almost surely, 243320432041113 is an apocalyptic number.

It is an amenable number.

43320432041113 is a deficient number, since it is larger than the sum of its proper divisors (1).

43320432041113 is an equidigital number, since it uses as much as digits as its factorization.

43320432041113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 43320432041113 its reverse (31114023402334), we get a palindrome (74434455443447).

The spelling of 43320432041113 in words is "forty-three trillion, three hundred twenty billion, four hundred thirty-two million, forty-one thousand, one hundred thirteen".