Base | Representation |
---|---|
bin | 10011101100110010100101… |
… | …11101101001110010011001 |
3 | 12200101101121101121112202011 |
4 | 21312121102331221302121 |
5 | 21134230221100303423 |
6 | 232045044242305521 |
7 | 12060540455521243 |
oct | 1166312275516231 |
9 | 180341541545664 |
10 | 43320432041113 |
11 | 12892101586a37 |
12 | 4a379590582a1 |
13 | 1b23139c80506 |
14 | a9aa11d41093 |
15 | 501ce577cb0d |
hex | 276652f69c99 |
43320432041113 has 2 divisors, whose sum is σ = 43320432041114. Its totient is φ = 43320432041112.
The previous prime is 43320432041111. The next prime is 43320432041129. The reversal of 43320432041113 is 31114023402334.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23221681556544 + 20098750484569 = 4818888^2 + 4483163^2 .
It is a cyclic number.
It is not a de Polignac number, because 43320432041113 - 21 = 43320432041111 is a prime.
Together with 43320432041111, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (43320432041111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21660216020556 + 21660216020557.
It is an arithmetic number, because the mean of its divisors is an integer number (21660216020557).
Almost surely, 243320432041113 is an apocalyptic number.
It is an amenable number.
43320432041113 is a deficient number, since it is larger than the sum of its proper divisors (1).
43320432041113 is an equidigital number, since it uses as much as digits as its factorization.
43320432041113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 43320432041113 its reverse (31114023402334), we get a palindrome (74434455443447).
The spelling of 43320432041113 in words is "forty-three trillion, three hundred twenty billion, four hundred thirty-two million, forty-one thousand, one hundred thirteen".
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