Base | Representation |
---|---|
bin | 10011101100110010100101… |
… | …11101101001110010010111 |
3 | 12200101101121101121112202002 |
4 | 21312121102331221302113 |
5 | 21134230221100303421 |
6 | 232045044242305515 |
7 | 12060540455521241 |
oct | 1166312275516227 |
9 | 180341541545662 |
10 | 43320432041111 |
11 | 12892101586a35 |
12 | 4a3795905829b |
13 | 1b23139c80504 |
14 | a9aa11d41091 |
15 | 501ce577cb0b |
hex | 276652f69c97 |
43320432041111 has 2 divisors, whose sum is σ = 43320432041112. Its totient is φ = 43320432041110.
The previous prime is 43320432041063. The next prime is 43320432041113. The reversal of 43320432041111 is 11114023402334.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43320432041111 is a prime.
It is a super-2 number, since 2×433204320411112 (a number of 28 digits) contains 22 as substring.
Together with 43320432041113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43320432041113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21660216020555 + 21660216020556.
It is an arithmetic number, because the mean of its divisors is an integer number (21660216020556).
Almost surely, 243320432041111 is an apocalyptic number.
43320432041111 is a deficient number, since it is larger than the sum of its proper divisors (1).
43320432041111 is an equidigital number, since it uses as much as digits as its factorization.
43320432041111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 43320432041111 its reverse (11114023402334), we get a palindrome (54434455443445).
The spelling of 43320432041111 in words is "forty-three trillion, three hundred twenty billion, four hundred thirty-two million, forty-one thousand, one hundred eleven".
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