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4332204021134 = 211196918364597
BaseRepresentation
bin111111000010101011011…
…110110101010110001110
3120100011011202011111122202
4333002223132311112032
51031434323212134014
613114104223041502
7624664024412063
oct77025336652616
916304152144582
104332204021134
111420306258670
1259b73a440292
132556a97cb142
1410d9734d2c6a
1577a55a063de
hex3f0ab7b558e

4332204021134 has 8 divisors (see below), whose sum is σ = 7089061125528. Its totient is φ = 1969183645960.

The previous prime is 4332204021113. The next prime is 4332204021139. The reversal of 4332204021134 is 4311204022334.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 4332204021097 and 4332204021106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4332204021139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 98459182277 + ... + 98459182320.

It is an arithmetic number, because the mean of its divisors is an integer number (886132640691).

Almost surely, 24332204021134 is an apocalyptic number.

4332204021134 is a deficient number, since it is larger than the sum of its proper divisors (2756857104394).

4332204021134 is a wasteful number, since it uses less digits than its factorization.

4332204021134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 196918364610.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 4332204021134 its reverse (4311204022334), we get a palindrome (8643408043468).

The spelling of 4332204021134 in words is "four trillion, three hundred thirty-two billion, two hundred four million, twenty-one thousand, one hundred thirty-four".

Divisors: 1 2 11 22 196918364597 393836729194 2166102010567 4332204021134