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43325125141 = 172548536773
BaseRepresentation
bin101000010110011000…
…001111001000010101
311010211101212101200111
4220112120033020111
51202212213001031
631523035443021
73062431326124
oct502630171025
9133741771614
1043325125141
11174129a3851
1284915b6471
134115c20a2c
142150047abb
1511d889e1b1
hexa1660f215

43325125141 has 4 divisors (see below), whose sum is σ = 45873661932. Its totient is φ = 40776588352.

The previous prime is 43325125091. The next prime is 43325125163. The reversal of 43325125141 is 14152152334.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 19896230916 + 23428894225 = 141054^2 + 153065^2 .

It is a cyclic number.

It is not a de Polignac number, because 43325125141 - 27 = 43325125013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43325125171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1274268370 + ... + 1274268403.

It is an arithmetic number, because the mean of its divisors is an integer number (11468415483).

Almost surely, 243325125141 is an apocalyptic number.

It is an amenable number.

43325125141 is a deficient number, since it is larger than the sum of its proper divisors (2548536791).

43325125141 is a wasteful number, since it uses less digits than its factorization.

43325125141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2548536790.

The product of its digits is 14400, while the sum is 31.

Adding to 43325125141 its reverse (14152152334), we get a palindrome (57477277475).

The spelling of 43325125141 in words is "forty-three billion, three hundred twenty-five million, one hundred twenty-five thousand, one hundred forty-one".

Divisors: 1 17 2548536773 43325125141