Base | Representation |
---|---|
bin | 101000010110011000… |
… | …001111001000010101 |
3 | 11010211101212101200111 |
4 | 220112120033020111 |
5 | 1202212213001031 |
6 | 31523035443021 |
7 | 3062431326124 |
oct | 502630171025 |
9 | 133741771614 |
10 | 43325125141 |
11 | 174129a3851 |
12 | 84915b6471 |
13 | 4115c20a2c |
14 | 2150047abb |
15 | 11d889e1b1 |
hex | a1660f215 |
43325125141 has 4 divisors (see below), whose sum is σ = 45873661932. Its totient is φ = 40776588352.
The previous prime is 43325125091. The next prime is 43325125163. The reversal of 43325125141 is 14152152334.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 19896230916 + 23428894225 = 141054^2 + 153065^2 .
It is a cyclic number.
It is not a de Polignac number, because 43325125141 - 27 = 43325125013 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43325125171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1274268370 + ... + 1274268403.
It is an arithmetic number, because the mean of its divisors is an integer number (11468415483).
Almost surely, 243325125141 is an apocalyptic number.
It is an amenable number.
43325125141 is a deficient number, since it is larger than the sum of its proper divisors (2548536791).
43325125141 is a wasteful number, since it uses less digits than its factorization.
43325125141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2548536790.
The product of its digits is 14400, while the sum is 31.
Adding to 43325125141 its reverse (14152152334), we get a palindrome (57477277475).
The spelling of 43325125141 in words is "forty-three billion, three hundred twenty-five million, one hundred twenty-five thousand, one hundred forty-one".
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