Base | Representation |
---|---|
bin | 101000010110100111… |
… | …000001001000000101 |
3 | 11010211200011020220121 |
4 | 220112213001020011 |
5 | 1202214210444231 |
6 | 31523254501541 |
7 | 3062506264663 |
oct | 502647011005 |
9 | 133750136817 |
10 | 43328999941 |
11 | 174150aaa67 |
12 | 84929648b1 |
13 | 4116979606 |
14 | 2150775c33 |
15 | 11d8db7311 |
hex | a169c1205 |
43328999941 has 2 divisors, whose sum is σ = 43328999942. Its totient is φ = 43328999940.
The previous prime is 43328999933. The next prime is 43329000037. The reversal of 43328999941 is 14999982334.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23822687716 + 19506312225 = 154346^2 + 139665^2 .
It is a cyclic number.
It is not a de Polignac number, because 43328999941 - 23 = 43328999933 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 43328999941.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (43328999041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21664499970 + 21664499971.
It is an arithmetic number, because the mean of its divisors is an integer number (21664499971).
Almost surely, 243328999941 is an apocalyptic number.
It is an amenable number.
43328999941 is a deficient number, since it is larger than the sum of its proper divisors (1).
43328999941 is an equidigital number, since it uses as much as digits as its factorization.
43328999941 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15116544, while the sum is 61.
The spelling of 43328999941 in words is "forty-three billion, three hundred twenty-eight million, nine hundred ninety-nine thousand, nine hundred forty-one".
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