4334401231 has 2 divisors, whose sum is σ = 4334401232. Its totient is φ = 4334401230.

The previous prime is 4334401189. The next prime is 4334401237. The reversal of 4334401231 is 1321044334.

4334401231 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4334401231 - 2¹⁵ = 4334368463 is a prime.

It is a super-2 number, since 2×4334401231² = 37574068062588630722, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4334401196 and 4334401205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4334401237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2167200615 + 2167200616.

It is an arithmetic number, because the mean of its divisors is an integer number (2167200616).

Almost surely, 2^4334401231 is an apocalyptic number.

4334401231 is a deficient number, since it is larger than the sum of its proper divisors (1).

4334401231 is an equidigital number, since it uses as much as digits as its factorization.

4334401231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

The square root of 4334401231 is about 65836.1696258219. The cubic root of 4334401231 is about 1630.4583290907.

Adding to 4334401231 its reverse (1321044334), we get a palindrome (5655445565).

The spelling of 4334401231 in words is "four billion, three hundred thirty-four million, four hundred one thousand, two hundred thirty-one".