Search a number
-
+
4334403552181 is a prime number
BaseRepresentation
bin111111000100101110100…
…101011000001110110101
3120100100212000222021000121
4333010232211120032311
51032003324302132211
613115110354411541
7625102363206043
oct77045645301665
916310760867017
104334403552181
11142123489791a
125a0052b90bb1
1325596a3c71c1
1410db0168b393
1577b33b7e271
hex3f12e9583b5

4334403552181 has 2 divisors, whose sum is σ = 4334403552182. Its totient is φ = 4334403552180.

The previous prime is 4334403552139. The next prime is 4334403552203. The reversal of 4334403552181 is 1812553044334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2618279972100 + 1716123580081 = 1618110^2 + 1310009^2 .

It is a cyclic number.

It is not a de Polignac number, because 4334403552181 - 27 = 4334403552053 is a prime.

It is a super-2 number, since 2×43344035521812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4334403532181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2167201776090 + 2167201776091.

It is an arithmetic number, because the mean of its divisors is an integer number (2167201776091).

Almost surely, 24334403552181 is an apocalyptic number.

It is an amenable number.

4334403552181 is a deficient number, since it is larger than the sum of its proper divisors (1).

4334403552181 is an equidigital number, since it uses as much as digits as its factorization.

4334403552181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 43.

The spelling of 4334403552181 in words is "four trillion, three hundred thirty-four billion, four hundred three million, five hundred fifty-two thousand, one hundred eighty-one".