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43354224220709 is a prime number
BaseRepresentation
bin10011101101110001100010…
…01000100101101000100101
312200111121211102120010120102
421312320301020211220211
521140303422400030314
6232112353342113445
712063145043355263
oct1166706110455045
9180447742503512
1043354224220709
11128a547236a696
124a42409b7b885
131b26393ba225c
14a9c4d9c83433
15502b2227a5de
hex276e31225a25

43354224220709 has 2 divisors, whose sum is σ = 43354224220710. Its totient is φ = 43354224220708.

The previous prime is 43354224220691. The next prime is 43354224220711. The reversal of 43354224220709 is 90702242245334.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 43101562171684 + 252662049025 = 6565178^2 + 502655^2 .

It is a cyclic number.

It is not a de Polignac number, because 43354224220709 - 216 = 43354224155173 is a prime.

Together with 43354224220711, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (43354224220789) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21677112110354 + 21677112110355.

It is an arithmetic number, because the mean of its divisors is an integer number (21677112110355).

Almost surely, 243354224220709 is an apocalyptic number.

It is an amenable number.

43354224220709 is a deficient number, since it is larger than the sum of its proper divisors (1).

43354224220709 is an equidigital number, since it uses as much as digits as its factorization.

43354224220709 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2903040, while the sum is 47.

The spelling of 43354224220709 in words is "forty-three trillion, three hundred fifty-four billion, two hundred twenty-four million, two hundred twenty thousand, seven hundred nine".